Please help anyone if you can This one is really confusing me I need the IQR for these set of numbers
0.10,0.18,0.20,0.21,0.24,0.24,0.25,0.26,0.28
What I did was place them in order and worked my way from both end until I got in the middle I came up with 0.24 but not sure if it's right
0.24 is the median.
The interquartile range is between the 1st and 3rd quartiles.
Check this site for figuring the IQR.
http://wiki.answers.com/Q/What_is_the_interquartile_range
9 terms, so median is 24
first quartile .19
third quartile .255
IQR= .255-.19=.065 or .07
thank you both Ms. Sue for the site and bobpursley for assisting me in this problem.
You're welcome.
To find the interquartile range (IQR), you need to determine the lower quartile (Q1) and the upper quartile (Q3) of the data set. Here's how you can do it step by step:
1. Arrange the numbers in ascending order:
0.10, 0.18, 0.20, 0.21, 0.24, 0.24, 0.25, 0.26, 0.28
2. Calculate Q1 (the lower quartile):
To find Q1, you need to determine the median of the lower half of the data set. Since the data set has an odd number of values (9 in this case), the median is the middle value, which is 0.21.
3. Calculate Q3 (the upper quartile):
To find Q3, you need to determine the median of the upper half of the data set. Again, since the data set has an odd number of values, the median is the middle value, which is 0.25.
4. Calculate the IQR:
The IQR is the difference between Q3 and Q1. So, IQR = Q3 - Q1 = 0.25 - 0.21 = 0.04
Therefore, the interquartile range (IQR) for the given set of numbers is 0.04.
Your initial calculation of 0.24 is incorrect as the value you arrived at represents the median, not the IQR.