how do you go about finding y-intercept and the slope for the equation -2y+3y=-21
One of the y's in your equation should probably be an x. Please verify your typing.
Rewrite your equation (after correcting it) into y = mx + b form.
m will be the slope and b will be the y-intercept, where the straight line crosses the y axis.
-2y+3y = -21
y(-2+3)= -21
y(1)= -21
y = -21 + (-1)
y = -21 - 1
y = -22
miyako's answer is incorrect. If both terms on the left contain a y, then y = -21. You would have a horizontal line with zero slope.
I still believe one of your x's should be a y
move the x1,y1,x2, and y2 sliders back and forth.which sliders affect the rise?
To find the y-intercept and slope for the equation -2y + 3x = -21, you need to rearrange the equation to the slope-intercept form, which is y = mx + b. In this form, 'm' represents the slope, and 'b' represents the y-intercept.
Let's start by rearranging the equation:
-2y + 3x = -21
First, get rid of the coefficient of '-2' in front of 'y' by dividing the entire equation by '-2':
(-2y + 3x) / -2 = -21 / -2
y - (3/2)x = 10.5
Next, rewrite the equation in slope-intercept form by isolating 'y':
y = (3/2)x + 10.5
Now we can identify the slope and the y-intercept:
The coefficient of 'x', which is (3/2), represents the slope.
The constant term at the end of the equation, which is 10.5, represents the y-intercept.
Therefore, the slope (m) is 3/2, and the y-intercept (b) is 10.5.