an ice cube at 0 was dropped into 30.0 g of water in a cup at 45.0 C at the instant that all of the ice was melted, the tempature of the water in the cup was 19.5 C. what was the mass of the icecube?
The sum of the heats gained is zero (water has negative heat gained).
Heat gained ice+heatgainedwater=0
M*Lf+30*cwater*(19.5-45)=0
solve for M. You have to know the heat of fusion, and the specific heat of water, IN THE CORRECT UNITS>
0,0095876946kg
that is what i'm trying to figure out to
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a perfect square ice cube measures 3 cm on each side. It has a mass of 24.6g. What is the density of the ice cube?
To determine the mass of the ice cube, we can use the principle of conservation of energy, specifically the heat transferred equation, which states that:
Heat lost by hot object = Heat gained by cold object
First, let's calculate the heat lost by the hot water. We'll use the formula:
Heat lost = (mass of water) × (change in temperature) × (specific heat capacity of water)
Given:
Mass of water = 30.0 g
Change in temperature = final temperature - initial temperature = 19.5°C - 45.0°C = -25.5°C
Specific heat capacity of water = 4.18 J/g°C (this value represents how much heat energy is required to raise the temperature of 1g of water by 1°C)
Heat lost = (30.0 g) × (-25.5°C) × (4.18 J/g°C)
= -3158.5 J
Since heat is lost by the hot water, the same amount of heat is gained by the ice.
Next, let's determine the heat gained by the ice. We can use the formula:
Heat gained = (mass of ice) × (change in temperature) × (specific heat capacity of ice)
Given:
Change in temperature = final temperature of the water - initial temperature of the ice = 19.5°C - 0°C = 19.5°C
Specific heat capacity of ice = 2.09 J/g°C (this value represents how much heat energy is required to raise the temperature of 1g of ice by 1°C)
Heat gained = (mass of ice) × (19.5°C) × (2.09 J/g°C)
To find the mass of the ice cube, we can set the two heat equations equal to each other:
(mass of ice) × (19.5°C) × (2.09 J/g°C) = - 3158.5 J
We can solve for the mass of the ice by rearranging the equation:
Mass of ice = - 3158.5 J / (19.5°C × 2.09 J/g°C)
Mass of ice ≈ -83.68 g
Based on the calculation, the mass of the ice cube is approximately 83.68 grams. Note that the negative sign indicates the mass of the ice was lost during the melting process (which is expected).