A thunderstorm has an electric field one night of 1.5 105 N/C. What is the magnitude of the electric force on an electron in such a field?
To find the electric force on an electron in an electric field, we can use the following formula:
F = qE
where F is the electric force, q is the charge of an electron, and E is the electric field. The charge of an electron is approximately -1.6 x 10^-19 C. So, we can plug in the values:
F = (-1.6 x 10^-19 C)(1.5 x 10^5 N/C)
F = -2.4 x 10^-14 N
Since we're asked for the magnitude of the electric force, we can ignore the negative sign, which indicates the direction of the force. So the magnitude of the electric force on an electron in such a field is:
F = 2.4 x 10^-14 N
To determine the magnitude of the electric force on an electron in a given electric field, we can use the equation:
F = q * E,
where F represents the magnitude of the electric force, q is the charge of the particle (in this case, the electron's charge), and E is the magnitude of the electric field.
The charge of an electron is approximately -1.6 x 10^-19 Coulombs (C).
Given that the magnitude of the electric field (E) is 1.5 x 10^5 N/C, we can substitute these values into the equation:
F = (-1.6 x 10^-19 C) * (1.5 x 10^5 N/C).
F = -2.4 x 10^-14 N.
The magnitude of the electric force on an electron in an electric field of 1.5 x 10^5 N/C is approximately 2.4 x 10^-14 N.
The magnitude of the electric force on an electron (q = -1.6 x 10^-19 C) in an electric field (E = 1.5 x 10^5 N/C) can be calculated using the equation:
F = Eq
where F is the magnitude of the electric force, E is the electric field, and q is the charge of the electron.
Plugging in the given values:
F = (1.5 x 10^5 N/C) * (-1.6 x 10^-19 C)
F = -2.4 x 10^-14 N
Therefore, the magnitude of the electric force on an electron in an electric field of 1.5 x 10^5 N/C is 2.4 x 10^-14 N.