Questions LLC
Login
or
Sign Up
Ask a New Question
Mathematics
Algebra
Trigonometry
solve: 2cosx-1=0
1 answer
cosx = 1/2 , the cosine is positive in I and IV
x = 60° or 300°
or x = π/3 or x = 5π/3
You can
ask a new question
or
answer this question
.
Related Questions
Determine the concavity and find the points of inflection.
y=2cosx + sin2x 0≤x≤2pi y'=-2sinx + 2cos2x y"=-2cosx-4sinx How do
prove that
(2cosx+1)(2cosx-1)= 1 +2cos2x
q2) a) write the equation cos2x + 8cosx+9=0 in terms of cosx and show that for cosx it has equal roots
q2b) show that there are
Find the derivative if y^3 + y = 2cosx
For the following equation, why cannot I not solve it? I keep getting an error.
-- 2cosx - 3 = 0 -- I first isolated for "x"
Find the limit of
(2cosx+3cosx-2)/(2cosx-1)as x tends to pi/3.
tanx+secx=2cosx
(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
Find the volume of the solid obtained by rotating the region in the first quadrant enclosed by the curves y= tanx and y=2cosx
How do you solve 6x + 12 + 2cosx = 0?
Having trouble verifying this identity...
cscxtanx + secx= 2cosx This is what I've been trying (1/sinx)(sinx/cosx) + secx = 2cosx