explain this expression to an equivalent standard form quadratic expression

(x+5)(4x-3)

FOIL:

-first outer inner last:
4x^2-3x+20x-15
-combine like terms:
4x^2+17x-15

im pretty sure this is what you are talking about. if not, sorry!

thanks !

hey, no problem!

To express the expression (x+5)(4x-3) in standard form, you need to multiply the terms together and combine like terms. Here's how you can do it step-by-step:

1. Start with the expression (x+5)(4x-3).
2. Apply the distributive property by multiplying the first term in the first parentheses (x) by both terms in the second parentheses (4x and -3). This gives you 4x^2 - 3x.
3. Similarly, multiply the second term in the first parentheses (+5) by both terms in the second parentheses (4x and -3). This gives you 20x - 15.
4. Now combine the like terms: 4x^2 - 3x + 20x - 15.
5. Simplify further by combining the x terms: 4x^2 + 17x - 15.

Therefore, the expression (x+5)(4x-3) is equivalent to the standard form quadratic expression 4x^2 + 17x - 15.