chemistry

the molar solubility of PbS, in a 0.150 M ammonium sulfide (NH4)2S solution is? The Ksp for PbS= 3.2E-28.

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asked by Tara
  1. ...........PbS ==> Pb^+2 + S^-2
    initial.....0.......0......0
    change......x.......+x.....+x
    final.......x........x......x
    Ksp = (Pb^+2)(S^-2) = 3.2E-28

    ..............(NH4)2S ==> 2NH4^+ + S^-2
    initial.......0.15M........0........0
    change.........-0.15......0.30......0.15
    final...........0..........0.30.....0.15

    Substitute into Ksp and solve for PbS.
    We want solubility PbS; therefore, we want to solve for x.
    PbS = x
    Pb^+2 = x
    S^-2 = x+0.15
    3.2E-28 = (x)(x+0.15).
    Solve for x.

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