I am doing a boiling point problem and don't know the value of i for the equation delta T = i(kb)(m)
solution contains 45.0g caffeine in 25.0 g benzene.
can caffeine (the solute) be dissociated into ion particles? If not, then it is just 1.
http://library.thinkquest.org/C006669/data/Chem/colligative/colligative.html
For caffeine, i = 1. USUALLY, i is greater than 1 for ionic compounds, not covalent ones.
To determine the value of i in the equation ΔT = i(kb)(m), you need to consider the number of particles formed in the solvent when the solute is dissolved. These particles can include molecules, ions, or formula units.
In this case, you have 45.0 g of caffeine dissolved in 25.0 g of benzene. To calculate the value of i, you need to compare the moles of caffeine to the moles of particles formed.
First, calculate the number of moles of caffeine:
Moles of caffeine = mass of caffeine / molar mass of caffeine
The molar mass of caffeine can be found in the periodic table, which is approximately 194.19 g/mol.
Moles of caffeine = 45.0 g / 194.19 g/mol
Next, calculate the moles of benzene:
Moles of benzene = mass of benzene / molar mass of benzene
The molar mass of benzene is approximately 78.11 g/mol.
Moles of benzene = 25.0 g / 78.11 g/mol
Now, compare the moles of caffeine and moles of benzene:
i = Moles of solute / Moles of solvent
i = Moles of caffeine / Moles of benzene
Now, substitute the values you calculated earlier to determine the value of i.
i = (45.0 g / 194.19 g/mol) / (25.0 g / 78.11 g/mol)
i = 2.29
Therefore, for this boiling point problem, the value of i is approximately 2.29.