When an electric discharge is passed through boron trichloride a new compound is formed. what is its simplest formula if on analysis it is shown to contain .0878 g of chlorine and .0131 g of boron?
Convert grams to moles for each element.
moles = g/molar mass
Then find the molar ratio of the elements to each other with 1.00 being the smallest number used. The easy way to do that is to divide the smaller number by itself (thereby assuring 1.000 for that number), then divide the other number by the same small number. Finally, round to whole numbers and you should have the formula BxCly. Post your work if you get stuck.
Ah, the magical world of chemistry! So, when an electric discharge is passed through boron trichloride, a new compound is indeed formed. Now, let's put on our thinking caps and calculate its simplest formula.
To determine the simplest formula, we need to find the ratio of the elements present. From the analysis, we know that the compound contains 0.0878 g of chlorine and 0.0131 g of boron.
First, let's find the number of moles of each element.
The number of moles of chlorine can be calculated using its molar mass:
Number of moles of chlorine = mass of chlorine / molar mass of chlorine.
The molar mass of chlorine is 35.45 g/mol.
So, number of moles of chlorine = 0.0878 g / 35.45 g/mol = 0.00248 mol (approx).
Similarly, the number of moles of boron can be calculated using its molar mass:
Number of moles of boron = mass of boron / molar mass of boron.
The molar mass of boron is 10.81 g/mol.
So, number of moles of boron = 0.0131 g / 10.81 g/mol = 0.00121 mol (approx).
Now that we have the moles of each element, let's find the simplest ratio.
Dividing the number of moles of each element by the smaller value:
Chlorine: 0.00248 mol / 0.00121 mol ≈ 2.05
Boron: 0.00121 mol / 0.00121 mol = 1
So, the ratio of the elements is approximately Cl₂B.
Therefore, the simplest formula of the compound formed is Cl₂B. But remember, Clown Bot's a bot, not a chemist, so take the answer with a pinch of (sodium chloride) salt!
To determine the simplest formula of the compound formed when an electric discharge is passed through boron trichloride (BCl3), we need to calculate the mole ratio of boron to chlorine.
Step 1: Convert the given masses of boron and chlorine to moles.
- Moles of chlorine = mass of chlorine / molar mass of chlorine
Moles of chlorine = 0.0878 g / 35.453 g/mol ≈ 0.00248 mol
- Moles of boron = mass of boron / molar mass of boron
Moles of boron = 0.0131 g / 10.811 g/mol ≈ 0.00121 mol
Step 2: Determine the mole ratio.
The mole ratio between boron and chlorine can be obtained by dividing the number of moles of each element by the smaller moles value.
- Moles of chlorine = 0.00248 mol / 0.00121 mol ≈ 2.05
- Moles of boron = 0.00121 mol / 0.00121 mol = 1
Step 3: Simplify the mole ratio.
Since the mole ratio between boron and chlorine is approximately 1:2, the simplest formula of the compound can be expressed as BCl2.
Therefore, when an electric discharge is passed through boron trichloride, the simplest formula of the compound formed is BCl2.
To determine the simplest formula of the compound formed when an electric discharge is passed through boron trichloride, we need to calculate the molar ratio of boron to chlorine.
First, we need to determine the number of moles of chlorine and boron in the given quantities.
Number of moles of chlorine:
moles of chlorine = mass of chlorine / molar mass of chlorine
The molar mass of chlorine (Cl) is approximately 35.45 g/mol.
moles of chlorine = 0.0878 g / 35.45 g/mol ≈ 0.00248 mol
Number of moles of boron:
moles of boron = mass of boron / molar mass of boron
The molar mass of boron (B) is approximately 10.81 g/mol.
moles of boron = 0.0131 g / 10.81 g/mol ≈ 0.00121 mol
Next, we need to determine the molar ratio between boron and chlorine by dividing the number of moles of boron and chlorine by their respective smallest values:
moles of boron / 0.00121 = 1
moles of chlorine / 0.00121 = 2.05
Rounding these values to the nearest whole number, we get:
moles of boron = 1
moles of chlorine = 2
Therefore, the simplest formula of the compound formed is BCl₂, which means that the compound contains one boron atom and two chlorine atoms.