3CO(g)+ Fe2O3(s) --> 2Fe(s) + 3CO2(g) + 24.7 kJ. How much heat is released when 56 grams of CO react?
3*28.01 g CO reacting produces 24.7 kJ heat.
Therefore, 56 g CO will produce
24.7 x 56/84.03 = ??
Well, I hope you're ready for this hot topic! Let's calculate the heat released using some chemistry clown math.
First, we need to find the molar mass of CO, which is 12 grams per mole of carbon plus 16 grams per mole of oxygen, giving us a total of 28 grams per mole of CO.
Next, we need to find the number of moles of CO in 56 grams. By dividing 56 grams by 28 grams per mole, we find that we have 2 moles of CO.
Now that we know we have 2 moles of CO, we can compare it to the balanced equation. According to the equation, 3 moles of CO react to produce 24.7 kJ of heat.
So, if 3 moles of CO produce 24.7 kJ of heat, then 2 moles of CO will produce 2/3 of that amount. Doing some division, we get:
(2/3) * 24.7 kJ = 16.467 kJ
Therefore, when 56 grams of CO react, approximately 16.467 kJ of heat will be released. Just remember, this answer would definitely put the "hot" in "hot topic"!
To find out how much heat is released when 56 grams of CO reacts, we need to use the given balanced chemical equation and the molar mass of CO.
Step 1: Determine the molar mass of CO:
The molar mass of carbon (C) is approximately 12.01 g/mol, and the molar mass of oxygen (O) is approximately 16.00 g/mol. Since CO contains one carbon atom and one oxygen atom, its molar mass is:
Molar mass of CO = 12.01 g/mol + 16.00 g/mol = 28.01 g/mol
Step 2: Convert the given mass of CO to moles:
The number of moles of CO can be calculated using the formula:
Number of moles = Mass / Molar mass
Number of moles of CO = 56 g / 28.01 g/mol = 2 moles
Step 3: Use the stoichiometry of the balanced chemical equation:
From the balanced chemical equation, we can see that the ratio of CO to heat released is 3:24.7 kJ.
This means that for every 3 moles of CO reacted, 24.7 kJ of heat is released.
Step 4: Calculate the amount of heat released for 2 moles of CO:
To find out how much heat is released for 2 moles of CO, we can use a proportion:
(2 moles CO / 3 moles CO) = (x kJ / 24.7 kJ)
Cross multiply and solve for x:
3x = 24.7 x 2
3x = 49.4
x = 49.4 / 3
x ≈ 16.47 kJ
Therefore, when 56 grams of CO react, approximately 16.47 kJ of heat is released.
To determine the amount of heat released when 56 grams of CO react, we need to use the balanced equation and the stoichiometry of the reaction.
Given: Balanced equation: 3CO(g) + Fe2O3(s) --> 2Fe(s) + 3CO2(g) + 24.7 kJ
First, we need to calculate the molar mass of CO (carbon monoxide).
Carbon (C) has a molar mass of 12.01 g/mol, and oxygen (O) has a molar mass of 16.00 g/mol. Since there is one carbon and one oxygen in CO, the molar mass of CO is 12.01 g/mol + 16.00 g/mol = 28.01 g/mol.
Next, we need to convert the given mass of CO into moles.
We can use the relationship:
moles = mass / molar mass
moles of CO = 56 g / 28.01 g/mol = 1.998 moles (rounded to three decimal places)
Now, we can use the stoichiometry of the balanced equation to determine the amount of heat released.
From the balanced equation, we can see that the molar ratio between CO and the heat released is 3:24.7 kJ.
So, for every 3 moles of CO, 24.7 kJ of heat is released.
We can set up a proportion to find the amount of heat released for 1.998 moles of CO:
(1.998 mol CO / 3 mol CO) = (x / 24.7 kJ)
Simplifying the proportion, we get:
x = (1.998 mol CO / 3 mol CO) * 24.7 kJ
Calculating this value, we find:
x = 16.5 kJ (rounded to one decimal place)
Therefore, when 56 grams of CO react, approximately 16.5 kJ of heat is released.