Given the reaction:

C8H16 + 12O2 --> 8CO2 + 8H2O
How many moles of H2O are produced when 11.2 liters of C8H16 gas, measured at STP, reacts completely?

thank you but I got 4.00 and it's incorrect.

11.2LC8H16/22.4L=.5
1mol/.5=8mol/x
.5*8=4

At STP, 1 mol = 22.4L

convert liters of C8H16 gas to moles
then, convert to moles of H2O by the mole ratio (look at the coefficients)

O2 is the limiting reagent so convert the moles of C8H16 to moles of O2 and then convert the moles of O2 to moles of H2O

I'm not sure...

Well, it's a gassy situation we have here! Let's calculate the moles of H2O produced. To start, we need to convert the 11.2 liters of C8H16 to moles using the ideal gas law at STP, which is about 1 mole of gas occupying 22.4 liters.

So, 11.2 liters / 22.4 liters per mole = 0.5 moles of C8H16.

According to the balanced equation, for every mole of C8H16, we produce 8 moles of H2O. So, if we have 0.5 moles of C8H16, we can expect:

0.5 moles C8H16 x 8 moles H2O / 1 mole C8H16 = 4 moles of H2O.

Ta-da! So, when 11.2 liters of C8H16 gas (measured at STP) reacts completely, we would produce 4 moles of H2O.

To determine the number of moles of H2O produced when 11.2 liters of C8H16 gas reacts completely, we need to follow these steps:

Step 1: Convert liters of C8H16 gas to moles.
To convert liters to moles, we will need to use the ideal gas law equation:

PV = nRT

Where:
P = pressure (STP = 1 atm)
V = volume (11.2 liters)
n = number of moles (unknown)
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature (STP = 273 K)

Rearranging the equation to solve for n gives us:

n = PV / RT

Plugging in the given values:
n = (1 atm) * (11.2 L) / (0.0821 L.atm/mol.K * 273 K)

Solving the equation will give the number of moles of C8H16 gas.

Step 2: Determine the stoichiometry of the balanced equation.
From the balanced equation:
C8H16 + 12O2 → 8CO2 + 8H2O

We can see that for every 8 moles of H2O produced, 1 mole of C8H16 reacts.

Step 3: Calculate moles of H2O produced.
Since we have determined the moles of C8H16 gas in Step 1, we can use the stoichiometric ratio to find the number of moles of H2O produced.

moles of H2O = (moles of C8H16) * (moles of H2O / moles of C8H16)

Substituting the values:
moles of H2O = (moles of C8H16) * (8 moles of H2O / 1 mole of C8H16)

Calculating this will give us the number of moles of H2O produced when 11.2 liters of C8H16 gas reacts completely at STP.