Chemistry

Glycine is an amino acid that can be abbreviated HGly. If 27.50mL of 0.120 M NaOH neutralizes 0.248 g of HGly,what is the molar mass of the amino acid?

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asked by Cliff
  1. How many moles of OH- do you have

    molesOH- = .0275*.120

    You need the same number of moles of HGly

    molesHGly=.268/molemassHGly

    solve for the molar mass of HGly.

  2. from the abbreviated formula it is a monoprotic acid. Thus the equation for the neutralisation is

    HGly + NaOH -> H2O + NaGly

    so one mole of HGly reacts with one mole of NaOH.

    number of moles of NaOH used is
    0.02750 L x 0.120 mole L^-1

    which is the same as the number of moles of HGly

    so as number of moles = mass/molar mass

    we can find the molar mass as mass (0.248 g) is given in the question.

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    posted by Dr Russ

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