# Chemistry

Glycine is an amino acid that can be abbreviated HGly. If 27.50mL of 0.120 M NaOH neutralizes 0.248 g of HGly,what is the molar mass of the amino acid?

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1. How many moles of OH- do you have

molesOH- = .0275*.120

You need the same number of moles of HGly

molesHGly=.268/molemassHGly

solve for the molar mass of HGly.

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2. from the abbreviated formula it is a monoprotic acid. Thus the equation for the neutralisation is

HGly + NaOH -> H2O + NaGly

so one mole of HGly reacts with one mole of NaOH.

number of moles of NaOH used is
0.02750 L x 0.120 mole L^-1

which is the same as the number of moles of HGly

so as number of moles = mass/molar mass

we can find the molar mass as mass (0.248 g) is given in the question.

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posted by Dr Russ

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