Glycine is an amino acid that can be abbreviated HGly. If 27.50mL of 0.120 M NaOH neutralizes 0.248 g of HGly,what is the molar mass of the amino acid?
How many moles of OH- do you have
molesOH- = .0275*.120
You need the same number of moles of HGly
molesHGly=.268/molemassHGly
solve for the molar mass of HGly.
from the abbreviated formula it is a monoprotic acid. Thus the equation for the neutralisation is
HGly + NaOH -> H2O + NaGly
so one mole of HGly reacts with one mole of NaOH.
number of moles of NaOH used is
0.02750 L x 0.120 mole L^-1
which is the same as the number of moles of HGly
so as number of moles = mass/molar mass
we can find the molar mass as mass (0.248 g) is given in the question.
To find the molar mass of the amino acid HGly, we can use the equation:
Molar mass (in g/mol) = mass (g) / moles
First, let's calculate the number of moles of HGly using the given information.
The molarity (M) of NaOH is given as 0.120 M, and the volume (V) used is 27.50 mL. We need to convert this volume to liters by dividing it by 1000:
V (in L) = 27.50 mL / 1000 = 0.0275 L
Now, we can calculate the number of moles (n) of NaOH using the formula:
n = M x V
n = 0.120 M x 0.0275 L = 0.0033 moles of NaOH
According to the balanced chemical equation between NaOH and HGly, the ratio is 1:1. So, the number of moles of HGly is also 0.0033 moles.
Next, we can calculate the molar mass of HGly using the given mass of HGly and the number of moles of HGly:
Molar mass (in g/mol) = mass (g) / moles
Molar mass (in g/mol) = 0.248 g / 0.0033 mol
Molar mass (in g/mol) ≈ 75.15 g/mol
Therefore, the molar mass of the amino acid HGly is approximately 75.15 g/mol.
To find the molar mass of the amino acid (HGly), you need to use the information given about the volume and concentration of NaOH used to neutralize a given mass of HGly. Here's the step-by-step explanation of how to solve this problem.
1. Write and balance the chemical equation for the neutralization reaction between NaOH and HGly. It is given that NaOH reacts with HGly in a 1:1 ratio based on the equation:
NaOH + HGly -> NaGly + H2O
2. Use the given volume and concentration of NaOH to calculate the number of moles of NaOH used.
Given: Volume of NaOH (V) = 27.50 mL = 0.0275 L
Concentration of NaOH (C) = 0.120 M
Moles of NaOH (n) = Volume (V) x Concentration (C)
= 0.0275 L x 0.120 M
3. Convert the mass of HGly given (0.248 g) to moles using its molar mass.
Remember, molar mass is the mass of one mole of a substance.
Let's assume the molar mass of HGly is M.
Moles of HGly = Mass (m) / molar mass (M)
= 0.248 g / M
4. According to the balanced equation, the ratio between moles of NaOH and moles of HGly is 1:1. Therefore, the number of moles of HGly used is also equal to the moles of NaOH used.
Moles of HGly = Moles of NaOH
5. Equate the two expressions obtained from step 3 and step 4.
0.248 g / M = 0.0275 L x 0.120 M
6. Solve the equation for the unknown molar mass (M).
M = (0.248 g) / (0.0275 L x 0.120 M)
7. Perform the calculation to find the molar mass of HGly.
M = 722.545 g/mol
Therefore, the molar mass of the amino acid HGly is approximately 722.545 g/mol.