You push a 250 kg desk with a force of 800N. The coefficient of friction is 0.2. What is the acceleration of the desk?
Remember the equation: deltaF = ma
In this case delta F is the force applied(800N)-Force of friction.
Now we need to find out the force of friction(Ff). We can do this through the equation Ff=uN.
u is given(.2)
N(the normal force)opposes the downward force of the desk(mg)250*9.81.
Thus Ff=.2*250*9.81=490.5
Back to the original equation, deltaF=ma. now all we do is plug in the values and solve for a.
800-490.5=250a
309.5/250=a
1.24=a
theres your answer, hope i helped
Omer is correct. Thanks for helping, Omer
To find the acceleration of the desk, we can use Newton's second law of motion, which states that the acceleration of an object is equal to the net force acting on it divided by its mass.
The net force acting on the desk is the force you exert minus the force of friction. The force of friction can be calculated using the formula:
Force of friction = coefficient of friction * normal force
The normal force is the perpendicular force exerted by a surface to support the weight of an object resting on it. In this case, it is equal to the weight of the desk, which can be calculated as:
Weight = mass * acceleration due to gravity
The acceleration due to gravity is approximately 9.8 m/s^2.
Now let's plug in the given values and calculate the acceleration.
Mass of the desk = 250 kg
Force exerted = 800 N
Coefficient of friction = 0.2
Acceleration due to gravity = 9.8 m/s^2
First, we calculate the weight:
Weight = mass * acceleration due to gravity
Weight = 250 kg * 9.8 m/s^2 = 2450 N
Next, we calculate the force of friction using the coefficient of friction and the weight:
Force of friction = coefficient of friction * normal force
Force of friction = 0.2 * 2450 N = 490 N
Now, to find the net force:
Net force = force exerted - force of friction
Net force = 800 N - 490 N = 310 N
Finally, we can calculate the acceleration using Newton's second law:
Acceleration = net force / mass
Acceleration = 310 N / 250 kg ≈ 1.24 m/s^2
Therefore, the acceleration of the desk is approximately 1.24 m/s^2.