2.) Bonnie is four years older than Clyde. Ten years ago she was twice his age. How old is Bonnie?

b=c+4

b-10=2(c-10)
(c+4)-10=2c-20
c-6=2c-20
c=14
b=14+4
Bonnie is 18 years old.

Thanks.:)

To solve this problem, let's assign variables to Bonnie and Clyde's ages.

Let's say Bonnie's current age is B and Clyde's current age is C.

We know that Bonnie is four years older than Clyde, so we can write the equation:

B = C + 4

We also know that ten years ago, Bonnie was twice Clyde's age. Let's calculate their ages ten years ago.

Bonnie's age ten years ago: B - 10
Clyde's age ten years ago: C - 10

According to the given information, ten years ago, Bonnie was twice Clyde's age, so we can write the equation:

B - 10 = 2 * (C - 10)

Now we can substitute the value of B from the first equation into the second equation:

C + 4 - 10 = 2 * (C - 10)

Simplifying the equation:

C - 6 = 2C - 20

Moving all the terms to one side:

2C - C = -20 + 6
C = 14

Now we can substitute the value of C into the first equation to find Bonnie's age:

B = 14 + 4
B = 18

Therefore, Bonnie is 18 years old.

To find out Bonnie's current age, we can set up an equation based on the information given.

Let's say Bonnie's current age is represented by B, and Clyde's current age is represented by C.

From the given information, we know that Bonnie is four years older than Clyde:
B = C + 4

We also know that ten years ago, Bonnie was twice Clyde's age:
B - 10 = 2(C - 10)

We can now solve this system of equations simultaneously to find Bonnie's age.

Substituting the value of B from the first equation into the second equation, we get:
(C + 4) - 10 = 2(C - 10)

Expanding the equation, we have:
C - 6 = 2C - 20

Now, let's solve for C:
C - 2C = -20 + 6
-C = -14
C = 14

Clyde is 14 years old.

To find Bonnie's age, we can substitute this value of C back into the first equation:
B = 14 + 4
B = 18

Bonnie is 18 years old.