A rocket moves upward, starting from rest with an acceleration of 35.0 m/s2 for 5.63 s. It runs out of fuel at the end of the 5.63 s but does not stop. How high does it rise above the ground?
To find the height that the rocket reaches, we can use the kinematic equation:
h = (1/2) * a * t^2
where:
h = height of the rocket
a = acceleration of the rocket
t = time
First, let's find the height using the given values.
Given:
a = 35.0 m/s^2
t = 5.63 s
Plugging these values into the equation, we get:
h = (1/2) * (35.0 m/s^2) * (5.63 s)^2
h = (1/2) * 35.0 * (31.73 s^2)
h = 17.5 * 31.73
h ≈ 555.275 m
Therefore, the rocket rises approximately 555.275 meters above the ground.