what is the answer to this systems of equation using elimination 2x+3y=11 and 3x+3y=18
To solve this system of equations using elimination, you can eliminate one variable by adding or subtracting the equations. Here's the step-by-step process:
1. Start with the two equations:
Equation 1: 2x + 3y = 11
Equation 2: 3x + 3y = 18
2. Notice that the coefficients of y in both equations are the same (3), so you can eliminate y by subtracting Equation 1 from Equation 2:
(3x + 3y) - (2x + 3y) = 18 - 11
3x - 2x + 3y - 3y = 7
x = 7
3. After finding the value of x, substitute it back into one of the original equations to solve for y. Let's use Equation 1:
2x + 3y = 11
2(7) + 3y = 11
14 + 3y = 11
3y = 11 - 14
3y = -3
y = -1
Therefore, the solution to the system of equations is x = 7 and y = -1.