# math

during the summer months, sarah makes and sells necklaces on the beach. last summer she sold the nacklaces for \$10 each. Her sales averaged 20 per day. Considering a price increase, she took a small survey and found that for every dollar increase, she would lose two sales a day. If the material for each necklaces costs \$6, what should her selling price be to maximize the profit?

pls i really need your help for this one. have tried all my best but i don't get it. my teacher didn't teach us yet. she said we should do it on our own

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1. If your teacher has not taught anything yet, then try the following, which works for anyone:

Make a table of the number of necklaces sold and the profit.

At \$10 a necklace, she sells 20 a day with a profit of \$4 each, so her net profit is \$4*20=\$80/day.

At \$11 a necklace, she sells 18 a day with a profit of \$5 each, so her net profit is \$5*18=\$90/day.

At \$12 a necklace, she sells 16 a day with a profit of \$6 each, so her net profit is \$6*16=\$96/day.

...
Continue this way until the profit drops, then take the highest profit.

If I were you, I would go for the \$0.50 increase/decrease once the highest profit is known.

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2. at \$19 a necklace, she sells 2 a day, so her net profit is \$2.
is that right

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posted by ted
3. At \$19 a necklace, her profit is \$19-\$6=\$13 for each necklace she sells. So her net profit is \$13*2 necklaces = \$26.

But \$26 is lower than \$96 when she would sell them at \$12 a necklace.

So continue with \$13, \$14, ... until the net profit goes down. Then choose the price that would give the highest profit.

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