Find sin(θ), cos(θ), tan(θ). Assume a = 40, b = 9, and c = 41. (Do not use mixed numbers in your answers.)
Okay for some reason I keep getting this problem wrong. For sin(θ) I put 9/41, but it's wrong. Could someone please tell what I did wrong.
sin(θ)=opposite/hypotenuse
I don't have the picture of the triangle in front of me. Double check if b corresponds to the side opposite to θ and c correspond to the hypotenuse side.
To find sin(θ), cos(θ), and tan(θ), we need to use the values of a, b, and c from a right triangle.
The sine function (sin) is defined as the ratio of the length of the side opposite the angle (b) divided by the length of the hypotenuse of the triangle (c). So sin(θ) = b / c.
Since you have been given the values a = 40, b = 9, and c = 41, the correct calculation for sin(θ) would be sin(θ) = 9 / 41. Therefore, your answer is correct.
If you are being marked incorrect despite providing the correct answer, it is possible that there might be a mistake in the system or there could be other factors causing the error. I would recommend double-checking your input or reaching out to your instructor or the platform you are using for clarification.
Similarly, to find cos(θ), which is the ratio of the length of the side adjacent to the angle (a) divided by the length of the hypotenuse (c), the calculation would be cos(θ) = a / c.
Given a = 40 and c = 41, the correct calculation for cos(θ) would be cos(θ) = 40 / 41.
Finally, to find tan(θ), which is the ratio of the length of the side opposite the angle (b) divided by the length of the side adjacent to the angle (a), the calculation would be tan(θ) = b / a.
Using the values b = 9 and a = 40, the correct calculation for tan(θ) would be tan(θ) = 9 / 40.
Therefore, the correct answers for sin(θ), cos(θ), and tan(θ) would be:
sin(θ) = 9/41
cos(θ) = 40/41
tan(θ) = 9/40