How do you solve?

3-3sinx-2cos^2(x) = 0

how do you solve x2+16x-80/x2-16

explain/justify without converting to standard form.

3y=(x-4)2-9

the two (2) in the problem is squared.

quan is shoppin. he can buy 2 pairs of pants and 1 shirt for $79.85 before tax is added. he cab buy 1 pair of pants and 2 shirts for $69.85 before tax is added. how much does a shirt cost

y=240*x squared

nedd help n algebra 1

The 10th grade class at Johnsonville High School has 50 students. There are 20 students that take Algebra and 15 students that take Geometry. Five students take both Algebra and Geometry.

How many students in the 10th grade class are enrolled in neither Algebra nor Geometry?

To solve the given equation 3 - 3sin(x) - 2cos^2(x) = 0, we can use the trigonometric identities to simplify the equation and then find the values of x that satisfy it.

Step 1: Rewrite the equation using the identity cos^2(x) = 1 - sin^2(x).
3 - 3sin(x) - 2(1 - sin^2(x)) = 0

Step 2: Distribute the negative sign and simplify.
3 - 3sin(x) - 2 + 2sin^2(x) = 0
-2sin^2(x) - 3sin(x) + 1 = 0

Step 3: Rearrange the equation.
-2sin^2(x) - 3sin(x) + 1 = 0
-2sin^2(x) + sin(x) - 3sin(x) + 1 = 0
-2sin^2(x) + sin(x) - 3sin(x) + 1 = 0

Step 4: Factor the quadratic expression.
(-2sin(x) + 1)(sin(x) - 1) = 0

Step 5: Set each factor equal to zero and solve.
-2sin(x) + 1 = 0
sin(x) = 1/2

sin(x) - 1 = 0
sin(x) = 1

Step 6: Solve for x.
For sin(x) = 1/2, we can find the angle using the inverse sine function:
x = arcsin(1/2)
x = π/6 or 30° (in degrees)

For sin(x) = 1, we can find the angle using the inverse sine function:
x = arcsin(1)
x = π/2 or 90° (in degrees)

Therefore, the solutions to the equation 3 - 3sin(x) - 2cos^2(x) = 0 are:
x = π/6 + 2kπ, where k is an integer.
x = π/2 + 2kπ, where k is an integer.