1.) The average sound intensity inside a busy neighborhood restaurant is 3.*10^-5 W/M^2. How much energy goes into each ear (area = 2.1 * 10^-2 m^2) during a one hour meal?

2.) A member of an aircraft maintenance crew wears protective earplugs that reduce the sound intensity by a factor of 350. When a jet aircraft is taking off, the sound intensity level experienced by the crew member is 88 dB. What sound intensity level would the crew member experience if he removed the protective earplugs.

STEPs please. thanks

To answer your questions step-by-step:

Question 1:
Step 1: Identify the given information:
- Sound intensity inside the restaurant = 3 * 10^-5 W/m^2
- Area of each ear = 2.1 * 10^-2 m^2
- Duration of the meal = 1 hour

Step 2: Calculate the energy received by each ear during a one-hour meal:
- Energy = Intensity * Area * Time
- Energy = (3 * 10^-5 W/m^2) * (2.1 * 10^-2 m^2) * (3600 seconds)
- Convert seconds to hours (1 hour = 3600 seconds)
- Energy = (3 * 10^-5 W/m^2) * (2.1 * 10^-2 m^2) * 3600 s
- Energy = 0.2268 J

Answer: The energy that goes into each ear during a one-hour meal is approximately 0.2268 Joules.

Question 2:
Step 1: Identify the given information:
- Reduction factor due to earplugs = 350
- Sound intensity level with earplugs on = 88 dB

Step 2: Calculate the sound intensity level without earplugs:
- Change the dB value to a regular intensity value in W/m^2 using the formula:
Intensity = 10^(dB/10) * Reference intensity
(Reference intensity = 10^-12 W/m^2)
- Intensity with earplugs on = 10^(88 dB/10) * 10^-12 W/m^2
- Intensity without earplugs = Intensity with earplugs / Reduction factor
- Intensity without earplugs = (10^(88 dB/10) * 10^-12 W/m^2) / 350

Step 3: Convert the intensity without earplugs back to dB:
- dB = 10 * log10(Intensity without earplugs / Reference intensity)
- dB = 10 * log10((10^(88 dB/10) * 10^-12 W/m^2) / 350 / 10^-12 W/m^2)
- dB ≈ 101.26 dB

Answer: The crew member would experience a sound intensity level of approximately 101.26 dB without the protective earplugs.

1.) To calculate the energy that goes into each ear during a one-hour meal in a busy neighborhood restaurant, you need to use the formula:

Energy = Intensity * Area * Time

Step 1: Convert the given average sound intensity into watts per square meter:

Sound intensity = 3 * 10^-5 W/m^2

Step 2: Calculate the energy by using the formula:

Energy = (Sound intensity) * (Area) * (Time)

Energy = (3 * 10^-5 W/m^2) * (2.1 * 10^-2 m^2) * (3600 s)

Energy = (3 * 2.1 * 10^-5 * 10^-2 * 3600) W

Energy = (3 * 2.1 * 10^-5 * 10^-2 * 3600) J

Energy = (3 * 2.1 * 10^-5 * 10^-2 * 3600) J

After calculating this expression, you should obtain the energy that goes into each ear during a one-hour meal in joules.

2.) To calculate the sound intensity level a crew member would experience if they removed the protective earplugs, you will need to use the formula:

Intensity level = 10 * log10 (Intensity1 / Intensity0)

Step 1: Convert the given sound intensity level with earplugs into watts per square meter:

Sound intensity level with earplugs = 88 dB

Step 2: Calculate the intensity with earplugs by rearranging the formula:

Intensity with earplugs = Intensity0 * 10^(Intensity level / 10)

Step 3: Calculate the intensity without earplugs by removing the earplugs:

Intensity without earplugs = Intensity with earplugs / reduction factor

Step 4: Calculate the sound intensity level without earplugs using the formula:

Sound intensity level without earplugs = 10 * log10(Intensity without earplugs / Intensity0)

After following these steps, you will find the sound intensity level a crew member would experience without the protective earplugs.