what voule of 12M hydrochloric acid must be diluted with distilled water to prepare 5.0L of 0.10M HCl?
L x M = L x M
.0416 l
To calculate the volume of 12M hydrochloric acid that must be diluted with distilled water to prepare 5.0L of 0.10M HCl, we can use the formula:
M1V1 = M2V2
Where:
M1 = Initial concentration of the solution (12M)
V1 = Initial volume of the solution (unknown)
M2 = Final concentration of the solution (0.10M)
V2 = Final volume of the solution (5.0L)
Rearranging the formula to solve for V1, we get:
V1 = (M2 * V2) / M1
Substituting the values into the formula:
V1 = (0.10M * 5.0L) / 12M
Now, let's calculate the volume of 12M hydrochloric acid needed:
V1 = (0.10 * 5.0) / 12
V1 = 0.05 / 12
V1 ≈ 0.0042 L or 4.2 mL
Therefore, approximately 4.2 mL of 12M hydrochloric acid must be diluted with distilled water to prepare 5.0L of 0.10M HCl.