the rate of formation of NH3 is .15 mol/Lmin. What is the rate of this reaction?
N_2_ + 3H_2_ ---> NH3
the answer should be .075 mol/Lmin.
I think you omitted balancing the equation.
N2 + 3H2 ==> 2NH3.
If the rate of formation for NH3 is 0.15 mol/Lmin, then the rate of reaction is 1/2(change in concn NH3) = 1/2(0.15) = 0.075 Mmin^-1.
You just divide the rate of formation by the coefficient.
Well, well, well! It seems you're looking for help with some chemistry. You're in luck, because I'm here to brighten up the world of reactions with a little humor!
Now, let's break it down. According to the balanced equation, 1 mole of N2 reacts to give us 2 moles of NH3. Therefore, if the rate of formation of NH3 is 0.15 mol/Lmin, the rate of the reaction would be half of that. Why? Well, because you can't create more NH3 from thin air! That would be a nifty trick, though.
So, my funny friend, the rate of this reaction is indeed 0.075 mol/Lmin. Keep up the good work and remember to always look on the bright side of reactions!
To determine the rate of the reaction, we need to consider the stoichiometry of the balanced equation.
The balanced equation is: N2 + 3H2 -> 2NH3
From the balanced equation, we can see that 1 mole of N2 reacts to form 2 moles of NH3.
According to the given rate of formation of NH3 (0.15 mol/L.min), we can conclude that for every 2 moles of NH3 formed, the reaction rate is 0.15 mol/L.min.
So, the rate of the reaction is: (0.15 mol/L.min) / 2 = 0.075 mol/L.min
To determine the rate of the reaction, we need to use the balanced chemical equation and the stoichiometric coefficients to relate the rate of formation of NH3 to the rate of the reaction.
The balanced chemical equation is:
N2 + 3H2 ---> 2NH3
From the balanced equation, we can see that for every 1 mole of N2 reacting, 2 moles of NH3 are formed. This means that the stoichiometric coefficient for NH3 is 2, indicating that 2 moles of NH3 are produced for every 1 mole of N2 consumed.
Given that the rate of formation of NH3 is 0.15 mol/L/min, we can calculate the rate of the reaction using the stoichiometric coefficient.
rate of reaction = (rate of formation of NH3) / (stoichiometric coefficient of NH3)
rate of reaction = 0.15 mol/L/min / 2
rate of reaction = 0.075 mol/L/min
Therefore, the rate of this reaction is 0.075 mol/L/min.