what is the molarity of a solution in which 80g of CaCl2 is dissolve in 2.5 L of solution?

To determine the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters).

Step 1: Calculate the number of moles of CaCl2.
The molar mass of CaCl2 is calculated as follows:
Ca: 1 × 40.08 g/mol = 40.08 g/mol
Cl: 2 × 35.45 g/mol = 70.90 g/mol
Total molar mass of CaCl2 = 40.08 g/mol + 70.90 g/mol = 110.98 g/mol

To find the number of moles, divide the given mass by the molar mass:
Number of moles = Mass / Molar mass
Number of moles = 80 g / 110.98 g/mol ≈ 0.721 mol

Step 2: Calculate the molarity of the solution.
Molarity (M) is defined as moles of solute divided by the volume of the solution in liters.
Molarity = Moles of solute / Volume of solution

Given that the volume of the solution is 2.5 L, the molarity is calculated as follows:
Molarity = 0.721 mol / 2.5 L ≈ 0.2884 M

Therefore, the molarity of the solution is approximately 0.2884 M.