The magnetic flux through a coil of wire changes from 8 Txm ^2 to zero in a time 0.5 s. what is the magnitude of the average voltage induced in the coil during this change?
please explain your answer..
Induced voltage is the rate of change of magnetic flux. That is Faraday's law.
Divide the flux change in T*m^2 units by the time in seconds and you will get the average induced voltage during the change
To find the magnitude of the average voltage induced in the coil during the change of magnetic flux, you can use Faraday's law of electromagnetic induction. According to Faraday's law, the magnitude of the induced voltage is equal to the rate of change of magnetic flux through the coil.
The formula to calculate the induced voltage is:
V = -(dΦ/dt)
Where:
V is the induced voltage
dΦ/dt is the rate of change of magnetic flux
In this case, the initial magnetic flux is given as 8 Txm^2, and it changes to zero in a time of 0.5 s.
To calculate the rate of change of magnetic flux, subtract the initial flux from the final flux and divide it by the time interval.
ΔΦ = Φ(final) - Φ(initial)
ΔΦ = 0 - 8 Txm^2 = -8 Txm^2
Δt = t(final) - t(initial)
Δt = 0.5 s - 0 s = 0.5 s
Now, plug the values into the formula to calculate the induced voltage:
V = -(dΦ/dt)
V = -(ΔΦ/Δt)
V = -(-8 Txm^2 / 0.5 s) = 16 Txm^2/s
Therefore, the magnitude of the average voltage induced in the coil during this change is 16 Txm^2/s.