Calculate q when a system does 54 J of work and its energy is increased by 61 J??
I know the total change in energy of a system is "q + w", but I don't don't how to apply this.
54j + 61j ???
To calculate the change in internal energy of a system, we can use the equation:
ΔE = q + w
where ΔE represents the change in energy, q represents heat transfer, and w represents work done.
In this case, we are given that the system does 54 J of work and its energy is increased by 61 J. Let's substitute these values into the equation:
61 J = q + 54 J
To calculate q, we need to isolate it on one side of the equation. We can do this by subtracting 54 J from both sides:
q = 61 J - 54 J
Now, we can simplify this equation:
q = 7 J
Therefore, the value of q is 7 J.
To calculate the value of q (heat transferred), we can use the equation:
ΔE = q + W
Where:
ΔE stands for the change in energy of the system
q represents the heat transferred to or from the system
W is the work done on or by the system
In this case, we are given that the work done on the system is 54 J (W = 54 J) and the change in energy is an increase of 61 J (ΔE = 61 J).
Substituting the given values into the equation, we have:
61 J = q + 54 J
We can now solve for q:
q = 61 J - 54 J
q = 7 J
Therefore, the heat transferred to the system (q) is 7 J.