Math

The diameter of a car's tire is 52 cm. While the car is being driven, the tire picks up a nail. How high above the ground will the nail be after the car has travelled 0.1 km?
It also asked me to graph this information. So I created a periodic graph that starts at 0 and then after half the circumference it is at 52 cm and then after the complete circumference it is back at 0.
But in the answers section of my textbook it started at -26 and after a complete rotation went back to -26. I was confused by this.

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  1. This looks like the bicycle wheel question I answered for you before.
    I agree with you that the -26 and +26 might be confusing.
    I think "they" considered the axle as the zero of elevation, so the lowest point in a rotation would be 26 cm below, and the highest point would be 26 above.
    However the wording referred to the height above ground level, so I would have put it as 0 to 52.

    Circumf of car's tire = 52π cm
    .1 km = 10 000 cm
    number of rotations at .1 km
    = 10 000/52π = 61.213

    So it is 0.213 into the 62nd rotation.
    Can you find how high it is?

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    posted by Reiny
  2. Thank you
    I found that at 0.213 of a cycle the distance travelled would be 34.8 cm in terms of the first cycle. And I found the height at that distance to be 22.15 cm
    Is that correct?

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    posted by Allison
  3. ブランド品激安卸販売専門店

    よく知らないんだけど、通販はバッグの専門店が行なっているだけで、シャネルとしては通販自体はまだ行ってないですよね?
    言わずもがなトートとか、シャネルのバッグと総称しても色んな種類があるんですけどね。

    スーパーコピー財布

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