interesting log problem

log base 2n 1944 = log base n (486* (2)^1/2)

find n^6

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asked by maya
  1. Let logbase2n 1944 = x

    (2n)^x = 2^x * n^x = 1944

    n^x = 486*2^1/2

    2^x * 486*2^1/2 = 1944
    2^x = 4*2^-1/2 = 2^3/2
    Therefore x = 3/2

    logbase2n 1944 = 3/2

    (2n)^3/2 = 1944
    Take the 2/3 power of both sides
    2n = 155.76
    n = 77.88

    n^6 will be quite large.

    See if you agree. I may have goofed somewhere

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    posted by drwls
  2. sounds quite right to me. thanks!

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    posted by maya

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