a barefoot field-goal kicker imparts a speed of 30 m/s to a football at rest. If the football has a mass of 0.50 kg and time of contact with the football is 0.0025 s, what is the force exerted on the foot?
6000
To calculate the force exerted on the foot, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
In this case, since the football is initially at rest and is given a speed of 30 m/s, we can find the acceleration using the formula: acceleration (a) = change in velocity / time.
The change in velocity can be calculated by subtracting the initial velocity (0 m/s) from the final velocity (30 m/s). Therefore, the change in velocity is 30 m/s.
Given that the time of contact with the football is 0.0025 s, we can calculate the acceleration: acceleration (a) = 30 m/s / 0.0025 s = 12000 m/s².
Now that we have the acceleration, we can calculate the force exerted on the foot using Newton's second law: force (F) = mass (m) × acceleration (a).
Plugging in the values, the force exerted on the foot is: F = 0.50 kg × 12000 m/s² = 6000 N.
So, the force exerted on the foot is 6000 Newtons.
Impulse = (Force)x(Time) = Momentum Change
= 15 kg*m/s
Solve for the Force, which will be in Newtons (kg m/s^2)