A saturated solution of PbSO4 has [Pb^2+] = 1.35E-4M. What is the concentration of SO4^2-?
thanks
PbSO4 ==> Pb^+2 + SO4^-2
If I look at the equation I see (SO4^-2) = (Pb^+2) don't I?
To find the concentration of SO4^2-, we can use the solubility product constant (Ksp) and the stoichiometry of the PbSO4 compound.
The balanced equation for the dissolution of PbSO4 is:
PbSO4 ↔ Pb2+ + SO4^2-
The solubility product constant expression is:
Ksp = [Pb2+] * [SO4^2-]
We are given that the [Pb2+] concentration is 1.35E-4M in the saturated solution.
Since the stoichiometry of the balanced equation shows that 1 mole of PbSO4 produces 1 mole of Pb2+ and 1 mole of SO4^2-, the concentration of SO4^2- is also equal to 1.35E-4M.
Therefore, the concentration of SO4^2- in the saturated solution of PbSO4 is 1.35E-4M.