What is the empirical formula for Ba(NO3)2
To determine the empirical formula for Ba(NO3)2, we need to find the simplest whole number ratio of atoms in the compound.
Step 1: Identify the elements present in the compound: Ba (barium) and (NO3)2 (nitrate).
Step 2: Determine the number of atoms for each element:
- Ba: 1 atom
- NO3: 2 atoms of nitrogen (N) and 6 atoms of oxygen (O)
Step 3: Simplify the ratios, if necessary:
- Divide the number of atoms by the greatest common divisor (in this case, 2) to simplify the ratio.
- Ba: 1/2
- N: 2/2 = 1
- O: 6/2 = 3
Step 4: Write the empirical formula using the simplified ratios:
- Ba(NO3)2 simplifies to BaN2O6.
Therefore, the empirical formula for Ba(NO3)2 is BaN2O6.
To determine the empirical formula for Ba(NO3)2, we need to find the simplest ratio of the elements present in the compound. Here's how you can do it:
Step 1: Identify the elements present in the compound.
In Ba(NO3)2, we have Barium (Ba), Nitrogen (N), and Oxygen (O).
Step 2: Determine the number of atoms of each element.
Ba(NO3)2 has one Barium (Ba) atom, two Nitrogen (N) atoms, and six Oxygen (O) atoms.
Step 3: Reduce the ratio to the simplest form.
Divide the number of atoms of each element by the greatest common divisor (GCD) to simplify the ratio.
Since the GCD of 1, 2, and 6 is 1, we divide by 1:
Ba(NO3)2 becomes BaN2O6.
So, the empirical formula for Ba(NO3)2 is BaN2O6.