I need help with this problem please
Calculate the amount of reagents you take to prepare 200 g of 9.0% (m/m) glucose solution? I already found the mass of the glucose which was part one and got 18.0 g of glucose. Now they want the mass of water and I am stuck.
9.0% w/w, means 9.0 g glucose per 100 g solution.If we want to prepare 200 g of solution, it must mean we need twice that g glucose or 9.0 x (200g soln/100 g soln) = 18.0 g glucose.
If the total mass of the solution is 200 g and the mass of the glucose is 18.0 g, the how much is the mass of the solvent>
mass soln total = mass solvent + mass solute.
200 = mass solvent + 18.0
mas solute = ....
Thank you i minused 18.0 from both sides to get 182g of water
To calculate the mass of water required to prepare a 200 g 9.0% (m/m) glucose solution, you first need to understand that the percentage (m/m) refers to the mass of the solute (glucose) in relation to the total mass of the solution.
In this case, you know that the mass of glucose is 18.0 g and the total mass of the solution is 200 g. The percentage (m/m) of glucose is given as 9.0%.
To find the mass of water, you need to consider that the mass of water and glucose combined should add up to the total mass of the solution. This means:
Mass of glucose + Mass of water = Total mass of the solution
Let's substitute the given values:
18.0 g + Mass of water = 200 g
Now, you can isolate the mass of water by subtracting the mass of glucose from both sides of the equation:
Mass of water = Total mass of the solution - Mass of glucose
Mass of water = 200 g - 18.0 g
Mass of water = 182.0 g
Therefore, you would need 182.0 g of water to prepare 200 g of a 9.0% (m/m) glucose solution.