Chemistry HELP

40.0 mL of 0.1880 M formic acid is titrated with 30.0 mL of 0.2010 M NaOH. Pka of formic acid is 3.8. What is the pH of the titration?

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2. 👎 0
3. 👁 125
1. moles formic acid = M x L = ??
moles NaOH = M x L = ??
pH = pKa + log [(formate)/(formic acid)]

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2. 👎 0
posted by DrBob222

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