Exprees each series using sigma notation.

3+6+9+12+15

sigma [ 3i] lower limit i = 1 , upper limit 5

To express the given series using sigma notation, we can observe that each term can be obtained by multiplying the corresponding position in the series by 3.

So, the sigma notation for the series 3+6+9+12+15 can be written as:

∑(3n), where n starts from 1 and goes up to the number of terms in the series (in this case, 5).

In sigma notation, it can be written as:

∑(3n) from n=1 to 5.

To express the given series using sigma notation, we need to find the pattern of the terms and determine the limits of the summation.

Let's observe the series: 3 + 6 + 9 + 12 + 15

We can see that each term is obtained by multiplying the corresponding position (starting from 1) by 3. So, the nth term of the series can be expressed as 3n.

The limits of the summation depend on the number of terms in the series. In this case, since we have 5 terms, the limits of the summation will be from 1 to 5.

Using the sigma notation, the series can be expressed as:

∑(from n = 1 to 5) 3n