calculate the theoretical number of moles of HCl equivalent to 1 mole of
a) NaHCO3
b)CaCO3
c)Al2O3
Write out the equations and tell me what you think.
a)HCl + NaHCO3 -> NaCl + H2O + CO2
b)2HCl + CaCO3 -> CaCl2 + H2CO3
-> CaCl2 + H2O + CO2
c) Al2O3 + HCl -> AlCl3 + H2O + O2
hmmm
a) 1mole
b) 2moles
3) 1
??
oh! is it right? i need to multiply the number of HCl to 1mol/6.022x10^(23)?
a)HCl + NaHCO3 -> NaCl + H2O + CO2
This is fine
b)2HCl + CaCO3 -> CaCl2 + H2CO3
-> CaCl2 + H2O + CO2
OK also
c) Al2O3 + HCl -> AlCl3 + H2O + O2
very few reactions yield O2
3HCl + Al2O3 ---> 2AlCl3 + 3H2O
a) 1 mole - agreed
b) 2 moles - agreed
3) here 3 moles
thank you. i'm just confused what to use to find the number of moles, when there's mass and other given.
thanks for the help.
To calculate the theoretical number of moles of HCl equivalent to a given compound, we need to consider the balanced chemical equation between the compound and HCl. Let's calculate it for each compound:
a) NaHCO3 (Sodium bicarbonate):
The balanced chemical equation between NaHCO3 and HCl is:
NaHCO3 + HCl -> NaCl + H2O + CO2
From the equation, it shows that 1 mole of NaHCO3 reacts with 1 mole of HCl. Therefore, the theoretical number of moles of HCl equivalent to 1 mole of NaHCO3 is also 1.
b) CaCO3 (Calcium carbonate):
The balanced chemical equation between CaCO3 and HCl is:
CaCO3 + 2HCl -> CaCl2 + H2O + CO2
From the equation, we can see that 1 mole of CaCO3 reacts with 2 moles of HCl. Therefore, the theoretical number of moles of HCl equivalent to 1 mole of CaCO3 is 2.
c) Al2O3 (Aluminum oxide):
The balanced chemical equation between Al2O3 and HCl is:
Al2O3 + 6HCl -> 2AlCl3 + 3H2O
From the equation, we can observe that 1 mole of Al2O3 reacts with 6 moles of HCl. Therefore, the theoretical number of moles of HCl equivalent to 1 mole of Al2O3 is 6.
In summary:
a) NaHCO3: 1 mole of HCl
b) CaCO3: 2 moles of HCl
c) Al2O3: 6 moles of HCl