10th grade

Suppose that a kid was casually sledding down a gentle slopping hill going 6 feet per second. Then, he hit a steeper part of the hill and started accelerating at a rate of 1.2 feet/second squared. At the bottom of the steep part of the hill he was going 10.56 feet/second. How long was the steep part of the this hill?

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asked by Anna
  1. "10th grade" is not the subject

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    posted by drwls
  2. The change in speed is 9.26 ft/s.

    Time spent accelerating = 9.26/1.2 = 7.72 seconds

    The average speed on the steep part was 5.88 ft/s

    Distance = 7.72 s * 5.88 ft/s= 45.4 feet

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    posted by drwls

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