# Pre-Calc

Can someone show me how to do this please. I am stuck.

find a number x such that
e^2x – 12e^x =13

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1. Substitute y=e^x to get a quadratic equation:
y²-12x+13=0
Solve for y.
Substitute the values of y=e^x into the original equation to make sure that all the roots are feasible/defined.
http://www.jiskha.com/display.cgi?id=1291874924

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posted by MathMate
2. let e^x = t
then
e^2x – 12e^x =13 becomes
t^2 - 12t - 13 = 0
(t-13)(t+1) = 0
t = 13 or t = -1

then e^x = 13 or e^x = -1
x = ln 13 or x = ln(-1)
but in ln(a) a > 0

so x = ln 13

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posted by Reiny
3. I slipped in the sign of the transformed equation. Instead of
y²-12x+13=0
y²-12x-13=0

Go with Reiny's solution.

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posted by MathMate
4. Thank u both

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posted by Roy

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