A satellite moves in a circular orbit around the Earth at a speed of 5661 m/s. (b) Determine the period of the satellite's orbit.

the satilites altitude above the surface of earth is 6076312.71m.
im using the equation P=2*pi*r/v and am coming up with 1.87 and its not right. i really need help!

You need to add the earth's radius (6378*10^3 m) to the altitude of the orbit (6076*10^3 m) to get the radius r of the orbit

To determine the period of the satellite's orbit, you can use the equation P = 2πr/v, where P represents the period, r represents the radius of the orbit, and v represents the satellite's velocity.

However, in this situation, you are given the satellite's speed and altitude instead of the radius. To calculate the radius, you can subtract the altitude from the radius of the Earth.

The radius of the Earth is approximately 6,371 kilometers, which is equivalent to 6,371,000 meters. Given that the satellite's altitude above the surface of the Earth is 6,076,312.71 meters, you can calculate the radius of the orbit as follows:

Radius of Orbit = Radius of Earth + Altitude
Radius of Orbit = 6,371,000 m + 6,076,312.71 m
Radius of Orbit = 12,447,312.71 m

Now that we have the radius of the orbit, we can substitute the values into the equation P = 2πr/v to find the period:

P = 2π * 12,447,312.71 m / 5661 m/s
P ≈ 43,717.24 s

The calculated period is approximately 43,717.24 seconds.