Calculate the weight percent of water in NiSO4 6H2O, how to calculate it?

To calculate the weight percent of water in NiSO4 · 6H2O, you need the molar mass of water (H2O) and the molar mass of NiSO4 · 6H2O.

1. Calculate the molar mass of water (H2O):
- Molar mass of hydrogen (H) = 1.008 g/mol
- Molar mass of oxygen (O) = 16.00 g/mol
- Molar mass of water (H2O) = (2 * Molar mass of hydrogen) + Molar mass of oxygen
= (2 * 1.008 g/mol) + 16.00 g/mol
= 18.016 g/mol

2. Calculate the molar mass of NiSO4 · 6H2O:
- Molar mass of nickel (Ni) = 58.69 g/mol
- Molar mass of sulfur (S) = 32.06 g/mol
- Molar mass of oxygen (O) = 16.00 g/mol
- Molar mass of water (H2O) = 18.016 g/mol (calculated in step 1)
- Molar mass of NiSO4 · 6H2O = (Molar mass of nickel) + (Molar mass of sulfur) + (4 * Molar mass of oxygen) + (6 * Molar mass of water)
= 58.69 g/mol + 32.06 g/mol + (4 * 16.00 g/mol) + (6 * 18.016 g/mol)

3. Calculate the weight percent of water in NiSO4 · 6H2O:
- Determine the molar mass of water in NiSO4 · 6H2O by multiplying the molar mass of water by 6.
- Compute the weight percent by dividing the molar mass of water in NiSO4 · 6H2O by the molar mass of the entire compound and multiplying by 100.

Let's do the calculations.

To calculate the weight percent of water in NiSO4 · 6H2O (nickel(II) sulfate hexahydrate), you need to determine the amount of water and the total molecular weight of the compound. Follow these steps:

1. Determine the total molecular weight of NiSO4 · 6H2O. You can do this by adding up the atomic masses of each element present in the compound. The atomic masses of nickel (Ni), sulfur (S), oxygen (O), and hydrogen (H) can be found in the periodic table.

2. Multiply the atomic mass of each element by the number of atoms present in the compound.

- For NiSO4, multiply the atomic mass of nickel by 1, the atomic mass of sulfur by 1, and the atomic mass of oxygen by 4 (since there are four oxygen atoms in NiSO4).

- For 6H2O, multiply the atomic mass of hydrogen by 12 (since there are 12 hydrogen atoms in 6 water molecules) and the atomic mass of oxygen by 6 (since there are 6 oxygen atoms in 6 water molecules).

3. Add up the total atomic masses obtained from step 2 to get the molecular weight of NiSO4 · 6H2O.

4. Determine the molecular weight of water (H2O) by adding the atomic mass of hydrogen and oxygen.

5. Calculate the weight percent of water by dividing the molecular weight of water by the molecular weight of NiSO4 · 6H2O and multiplying by 100.

Let's go through an example calculation:

1. Atomic masses:
- Nickel (Ni): 58.69 g/mol
- Sulfur (S): 32.07 g/mol
- Oxygen (O): 16.00 g/mol
- Hydrogen (H): 1.01 g/mol

2. Calculating the molecular weight of NiSO4 · 6H2O:
- Ni: 58.69 g/mol x 1 = 58.69 g/mol
- S: 32.07 g/mol x 1 = 32.07 g/mol
- O: 16.00 g/mol x 4 = 64.00 g/mol
- H: 1.01 g/mol x 12 = 12.12 g/mol
- O (from water): 16.00 g/mol x 6 = 96.00 g/mol
Total molecular weight = 262.88 g/mol

3. Molecular weight of water (H2O): 1.01 g/mol + 16.00 g/mol = 17.01 g/mol

4. Calculating the weight percent of water:
- Weight percent = (17.01 g/mol / 262.88 g/mol) x 100 = 6.47%

Therefore, the weight percent of water in NiSO4 · 6H2O is approximately 6.47%.

%H2O = (mass H2O/mass salt)*100

mass H2O is 6*molar mass H2O.
mass salt is molar mass of NiSO4.6H2O.

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