3x-2y=-5 and 4x+3y=-18
i need to graph and find the intersection
3x-2y = -5
4x+3y = -18
- - - - -
12x-8y = -20
12x+9y = -54
Now you just have to subtract normally.
12x - 8y = -20
-
12x + 9y = -54
-------------
0 -17y = 34
y = -2
From there, you can find the X
What?? im so confused i need to find the intersection like a point on a graph
y= -2 is one part of the point on the graph
4x+3y = -18
4x+3(-2) = -18
4x -6 = -18
4x = -12
x = 3
The intersection point would be (3,-2)
To graph the given system of equations, you can start by rearranging each equation to solve for y in terms of x. Let's solve the first equation for y:
3x - 2y = -5
-2y = -3x - 5
y = (3/2)x + (5/2)
Now let's solve the second equation for y:
4x + 3y = -18
3y = -4x - 18
y = (-4/3)x - 6
Now that we have both equations in slope-intercept form (y = mx + b), we can plot them on a graph.
For the first equation, start at the y-intercept, which is (0, 2.5), and then use the slope (rise over run) of 3/2. So, from the y-intercept, go up 3 units and to the right 2 units, and plot a point. Repeat this process a couple more times until you have enough points to draw a straight line.
For the second equation, again start at the y-intercept, which is (0, -6), and then use the slope of -4/3. So, from the y-intercept, go down 4 units and to the right 3 units, and plot another point. Repeat this process to get more points.
Now, graph both lines on the same coordinate plane.
The next step is to find the intersection point. This is the point where both lines on the graph meet. Simply locate the point where the two lines intersect, and this is your solution.
If the lines do not intersect or are parallel, it means there is no solution.
By graphing the lines, you can visually determine the intersection point and find your solution.