# alg 2

3x^2-243=

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1. to find 'x' you add 243 to both sides
so:
3x^2=243
divide both sides by 3
3x^2/3 = 243/3
x^2 = 81
then take the square root of both sides
so x=9
hope that helps, be sure to plug your numbers back in to check it take 9 and plug it in for x ::
3(9)^2-243
3(81)-243
243-243=0
0=0

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posted by Brittany
2. its 3x square root of that - 243
idk if that's how u work it.
idk what this is called

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posted by katelyn
3. its not finding the x!

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posted by katelyn

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