alg 2

3x^2-243=

asked by katelyn
  1. to find 'x' you add 243 to both sides
    so:
    3x^2=243
    divide both sides by 3
    3x^2/3 = 243/3
    x^2 = 81
    then take the square root of both sides
    so x=9
    hope that helps, be sure to plug your numbers back in to check it take 9 and plug it in for x ::
    3(9)^2-243
    3(81)-243
    243-243=0
    0=0

    posted by Brittany
  2. its 3x square root of that - 243
    idk if that's how u work it.
    idk what this is called

    posted by katelyn
  3. its not finding the x!

    posted by katelyn

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