Calculate the energy of a photon of light with a wavelength of 360 nm?

5.525 exponent -19

To calculate the energy of a photon, you can use the equation:

E = h * c / λ

where:
E is the energy of the photon,
h is Planck's constant (6.626 x 10^(-34) J*s),
c is the speed of light (3.0 x 10^8 m/s),
and λ is the wavelength of the light.

Plugging in the values, we have:

E = (6.626 x 10^(-34) J*s) * (3.0 x 10^8 m/s) / (360 x 10^(-9) m)

Simplifying this equation:

E = (6.626 x 3.0) / (360 x 10^(-9)) x (10^(-34) J*s x 10^8 m/s)

E = 19.878 / (3.6 x 10^(-1) x 10^(-9))

E = 19.878 / 3.6 x 10^(-10)

E = 5.521 x 10^(-8) J

Therefore, the energy of a photon with a wavelength of 360 nm is 5.521 x 10^(-8) Joules.

To calculate the energy of a photon of light, we can use the equation:

Energy (E) = Planck's constant (h) × Speed of light (c) / Wavelength (λ)

Where:
- Planck's constant (h) = 6.62607015 × 10^-34 J·s
- Speed of light (c) = 299,792,458 m/s
- Wavelength (λ) is given as 360 nm (nanometers), which is equal to 3.6 × 10^-7 meters.

First, convert the wavelength from nanometers to meters:

Wavelength (λ) = 3.6 × 10^-7 meters

Now, substitute the given values into the equation:

E = (6.62607015 × 10^-34 J·s) × (299,792,458 m/s) / (3.6 × 10^-7 meters)

Now, calculate the energy:

E ≈ 5.509 × 10^-19 Joules

Therefore, the energy of a photon of light with a wavelength of 360 nm is approximately 5.509 × 10^-19 Joules.

E = hc/wavelength