Hi,can I have your help? I'm just trying to solve a few Dilution Solution problems. I'm stuck on these two,and I wish you could help.
Here's one:
A 500 mL bottle of concentrated acetic acid is diluted to make a 5.0% solution. Find the volume of diluted that is prepared?
Normally,I apply the equation: M1V1=M2V2 to solve for the unknown. In this case I'm stuck,and wondering if that equation applies.
Here's the other problem:
If a 355 mL can of soda pop is diluted to a final volume of 1.00 L,what can be said quantitatively about the concentration of the diluted solution as compared with the original solution?
Thank You.
concentrated acetic acid? what is its strength? IF 100Percnet, then you want to dilute it 20 times (100 to 5). That means one part conc acid, 19 parts water.
so, 20x .5L is the final volume.
OK, diluting 1L from .355 L is 2.82 times, which means 1 part orig soda, 1.82 parts water. The new stuff is 1/2.82 times as conentrated. (about 1/3 the concentration)
Of course, I'd be happy to help you with your dilution solution problems!
Let's start with the first problem. You have a 500 mL bottle of concentrated acetic acid that you want to dilute to a 5.0% solution. You're right to consider using the equation M1V1 = M2V2, which is known as the dilution equation. However, in this case, we need to be slightly careful.
The dilution equation states that the initial concentration (C1) multiplied by the initial volume (V1) is equal to the final concentration (C2) multiplied by the final volume (V2). However, in this problem, we are not given the initial and final concentrations, but rather the final concentration and the initial volume.
To solve this problem, we can still use the dilution equation, but with a slight rearrangement. We can rewrite the equation as V2 = (C1 * V1) / C2. In this case, the initial concentration (C1) is the concentration of the concentrated acetic acid, which is not provided, and the final concentration (C2) is 5.0%. The initial volume (V1) is 500 mL, and we want to find the final volume (V2).
Since we don't know the concentration of the concentrated acetic acid, we can't solve this problem using the given information alone. You would need to know the initial concentration of the acetic acid in order to calculate the volume of diluted solution that is prepared.
Let's move on to the second problem. In this case, you have a 355 mL can of soda pop that you want to dilute to a final volume of 1.00 L. The question asks about the quantitative comparison of the concentration of the diluted solution to the original solution.
To compare the concentrations quantitatively, you can use the relationship between the volumes and concentrations of the original and diluted solutions. Since volume is directly proportional to concentration, we can say that the concentration of the diluted solution will be less than the concentration of the original solution.
In this case, the original solution (355 mL) is being diluted to a larger final volume of 1.00 L. Since the same amount of solute is being spread out over a larger volume, the concentration of the diluted solution will be lower.
So, quantitatively, we can say that the concentration of the diluted solution is lower than the concentration of the original solution when diluted to a larger volume.
I hope this helps! Let me know if there's anything else I can assist you with.