Login or Sign Up

Ask a New Question

Battery supplies a potential difference of 6v

At a certain temperature the current in the 45ohms resistor is 0.08A

How would you calculate the potential difference across the thermistor?

thanks :)

It depends on how the thermistor is connected. If connected in series:

Vtherm+Vr=6
Vtherm+45*.08=6

Similar Questions

The emf of a battery is equal to its terminal potential difference:A) under all conditions B) only when the battery is being

Top answer: Well done! Read more.
A circuit consists of a 12.0 V battery connected to three resistors 44 ohms, 15 ohms and 120 ohms in series.A)Find the current

Top answer: a. find Rtotal= sum resistors I=12/rtotal b. V44=I*44 Read more.
a battery has internal resistace of 4ohm and the emf is 12v .The battery used to maintain a current in a resistor of resistance

Top answer: current in circuit: 12/(24) = .5 amp potential on resister .5a*20ohm=10volts energy= I^2 R= .25*20=5 Read more.
A 10 ohm, 20 ohm lamp and 12v battery are connected in a parallel. A current of 1.8 A passes through the battery and a current

Top answer: R1 = 10 Ohms. R2 = 20 Ohms. I1 = 1.2A. 1. I1 + I2 = 1.8A. 1.2 + I2 = 1.8, I2 = 0.6A. 2. V = I1*R1 = Read more.
The graph below represents the relatonship between the potential difference across a metal conductor and the current through the

Top answer: To find the resistance of the conductor, we need to use Ohm's Law, which states that the potential Read more.
The graph below represents the relatonship between the potential difference across a metal conductor and the current through the

Top answer: resistance= voltage/current Read more.
A battery (ε= 6.20V, r = 0.100Ω) is connected to three light bulbs in parallels (R1= 6.00Ω, R2= 9.00Ω, R3= 18.0Ω).a)

Top answer: load resistance: 1/R= 1/6+1/9+1/18=(3+2+1)/18=6/18 R= 3 ohm current= 12/(3.1)= ... voltage lost on Read more.
A battery (ε=6.20 Vr =0.100Ω) is connected to three lightbulbs in parallels (R1=6.00Ω, R2=9.00Ω, R3=18.0Ω) (a) Calculate

Top answer: To answer these questions, we'll need to use Ohm's Law and the rules for calculating current and Read more.
When 2 resistors, R1 and R2 are connected in series across a 6V battery the potential difference across R1 is 4V. When R1 and R2

Top answer: Series Circuit. V1 = 4Volts. V2 = 6-4 = 2Volts. R1 = 2R3. Parallel Circuit. R2 = V/I = 6/0.45 = Read more.
Find the potential difference across R2 and the current through R2.(1 point) Responses Potential Difference = 6 V. Current = 6

Top answer: Since the question doesn't provide any information about the circuit, it is not possible to Read more.