One brand of laundry bleach is an aqueous solution containing 4.00% sodium hypochlorite (NaOCl) by mass

What is the molarity of this solution? (Assume a density of 1.02 g/mL .)

.54804

The question tells us that the concentration of the solution is 4.00% w/w.

That is 100 g of the solution contains 4.00 g NaOCl.
or
That is 1000 g of the solution contains 40.0 g NaOCl

The volume occupied by 1000 g is
mass/density
1000g/1.02 g ml^-1 = 980.4 ml

Molar mass of NaOCl is 74.44 g/mol

Number of moles of NaOCl is

40.0 g/74.44 g/mol = 0.5373 mole

so molarity is

moles/volume =

Well, that's a bleach-y question you've got there! To find the molarity of the solution, we need to know the molar mass of sodium hypochlorite. NaOCl has a molar mass of approximately 74.44 g/mol.

First, let's calculate the mass of sodium hypochlorite in the solution. If the solution has a density of 1.02 g/mL, then we have 1 mL of solution weighing 1.02 g. Since the solution is 4.00% sodium hypochlorite by mass, we can multiply the mass of the solution by 0.04 to get the mass of sodium hypochlorite:

1.02 g/mL * 0.04 = 0.0408 g/mL

Now, let's convert the mass of sodium hypochlorite to moles. We divide the mass by the molar mass:

0.0408 g/mL / 74.44 g/mol ≈ 0.000548 mol/mL

Finally, to get the molarity, we need to convert from mL to L (since Molarity is moles per liter):

0.000548 mol/mL * (1 L / 1000 mL) = 0.000548 M

So, the molarity of the solution is approximately 0.000548 M. Now you can clean those clothes with some mathematical magic!

To find the molarity of the solution, we need to know the concentration in moles per liter (M).

First, we need to calculate the number of moles of sodium hypochlorite present in 100 g of the solution. Since the concentration is given in mass percent, we assume that we have 100 g of the solution.

Step 1: Calculate the mass of sodium hypochlorite.
Mass of sodium hypochlorite = (4.00/100) * 100 g = 4.00 g

Step 2: Calculate the number of moles of sodium hypochlorite.
Molar mass of sodium hypochlorite (NaOCl) = (22.99 g/mol + 16.00 g/mol + 35.45 g/mol) = 74.44 g/mol
Number of moles = Mass / Molar mass = 4.00 g / 74.44 g/mol = 0.0537 mol

Now, we need to convert the volume of the solution to liters. Since we know the density of the solution is 1.02 g/mL, we can use this to convert the mass of the solution to volume.

Density = Mass / Volume
Volume = Mass / Density = 100 g / 1.02 g/mL = 98.04 mL = 0.09804 L

Finally, we can calculate the molarity of the solution.
Molarity (M) = Number of moles / Volume of solution in liters
M = 0.0537 mol / 0.09804 L = 0.548 M

Therefore, the molarity of the solution is approximately 0.548 M.