mike has two mats in the shape of triangles. the scale factor of the two mats is 7/9. what is the ratio of the perimeters?
I have no clue
since perimeter is linear,
the ration of their perimeters is 7/9
however, the ratio of their areas would be 49/81
7/9 IS THE ANSWER!!!!!!
To find the ratio of the perimeters of the two mats, you need to determine the relationship between the lengths of the sides of the two triangles.
Given that the scale factor of the two mats is 7/9, it means that corresponding side lengths on the two mats are proportional.
Let's assume that the two triangles have side lengths a, b, and c, and a', b', and c' respectively. The scale factor of 7/9 implies the following proportions:
a' = (7/9) * a
b' = (7/9) * b
c' = (7/9) * c
To find the ratio of the perimeters, add up all the side lengths of each mat. The perimeter P' of the second mat is given by:
P' = a' + b' + c' = (7/9) * a + (7/9) * b + (7/9) * c = (7/9) * (a + b + c)
Therefore, the ratio of the perimeters of the two mats is:
Ratio = P' / P = [(7/9) * (a + b + c)] / (a + b + c) = 7/9
Hence, the ratio of the perimeters of the two mats is 7/9.