Chemisty.....Help =))

What is the molarity of ZnCl2 that forms when 30.0g of zinc completely reacts with CuCl2 according to the following reaction? Assume a final volume of 285 mL . (please explain step by step I have no clue!)

Zn(s) + CuCl2(aq) --> ZnCl2(aq)+ Cu(s)

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  1. From the equation 1 mole of Zn(s) gives 1 mole of ZnCl2(aq)

    Number of moles of Zn is mass/molar mass of Zn
    30.0 g /65.39 g mole^-1
    =0.4588 mole

    so 0.4588 mole ZnCl2 is formed (because 1 mole of Zn(s) gives 1 mole of ZnCl2(aq))

    which is in 285 ml final volume

    molarity is moles/volume (in L)

    molarity =
    0.4588 mole/0.285 L

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    posted by Dr Russ
  2. l.64

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    posted by Blessing
  3. the answer is approximately 1.6098 M

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    posted by Bill

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