How many atoms of lead (Pb) are present in 0.75 moles?
To find how many atoms of lead (Pb) are present in 0.75 moles, you can use Avogadro's number, which relates the number of particles (in this case atoms) to the amount of substance (in this case moles). Avogadro's number is approximately equal to 6.022 x 10^23 particles per mole.
Here's how you can calculate it:
Step 1: Determine the molar mass of lead (Pb).
The molar mass of lead (Pb) is 207.2 grams per mole. You can find this value on the periodic table.
Step 2: Convert moles to grams.
Since you have 0.75 moles of lead (Pb), you can multiply this value by the molar mass of lead (Pb) to convert it to grams:
0.75 moles x 207.2 g/mol = 155.4 grams
Step 3: Convert grams to atoms.
To convert grams to atoms, you can use Avogadro's number. The formula is as follows:
Number of atoms = (Number of moles) x (Avogadro's number)
Number of atoms = (Number of grams) / (Molar mass) x (Avogadro's number)
Plugging in the values:
Number of atoms = 155.4 grams / 207.2 g/mol x (6.022 x 10^23 atoms/mol)
After performing the calculation, you'll find that there are approximately 4.53 x 10^23 atoms of lead (Pb) in 0.75 moles.