K we are learning about Linear Equations and Graphs. And I'm doing the Slope-point Form, but I'm kind of having troubles with it. Liek I don't really get how to change the slope point form to the slope intercept one.
Here is an example:
y-5 = -1/2(x+4)
y-5 = -1/2x-2
y-5+5 = -1/2x-2+5
y=-1/2x+3
-I don't get how x+4 turned into x-2. How did that happen?
x+4 did not turn into x-2, it turned into (-1/2)x - 2
you had (-1/2)(x+4)
now distribute the -1/2
to get (-1/2)x - 2
then they added 5 to both sides
for the final anwer of
y = (-1/2)x + 3
y = -0,5(x+4)+5
y = -0,5x - 2 + 5
y = -0,5x + 3
Actually, when you have a negative number before a bracket, you have to change the signs in the bracket.
So because of the -0,5, the X (which is positive) becomes negative and the +4 (wich is positive) becomes also negative.
Ok, thanks to both of u so much:)
To understand how x+4 turned into x-2, let's break down the steps:
Starting with the equation in slope-point form:
y - 5 = -1/2(x + 4)
To convert to slope-intercept form (y = mx + b), we want to isolate y on one side of the equation.
1. Distribute the -1/2 to the terms inside the parentheses:
y - 5 = -1/2x - 2
2. Next, add 5 to both sides of the equation to move the constant term to the right side:
y - 5 + 5 = -1/2x - 2 + 5
Simplifying the equation:
y = -1/2x + 3
Now let's focus on how x+4 turned into x-2.
In the original equation: y - 5 = -1/2(x + 4)
When we distribute -1/2 to both terms inside the parentheses (x and 4), we get:
-1/2(x + 4) = -1/2 * x - 1/2 * 4
= -1/2x - 2
So, x+4 became -1/2x - 2.
If you need further clarification, feel free to ask!