Sum of a 3 digit # is 24. Ones digit is 2 more than 2xs the hundred dig. Tens dig is 1 more thn 3xs the hund dig. Wats the #??

To find the three-digit number, let's break down the given information into equations.

Let's assume the hundreds digit is represented by 'x', the tens digit is represented by 'y', and the ones digit is represented by 'z'.

The sum of the three digits is given as 24, so we have our first equation:

x + y + z = 24

The ones digit is 2 more than 2 times the hundreds digit. This can be written as:

z = 2(2x) + 2

Simplifying this equation, we have:

z = 4x + 2

The tens digit is 1 more than 3 times the hundreds digit, which can be written as:

y = 3x + 1

Now, we can solve these three equations simultaneously to find the value of x, y, and z.

Using the first equation, we can express x in terms of y and z:

x = 24 - y - z

Substituting the value of x into the other two equations, we have:

z = 4(24 - y - z) + 2

and

y = 3(24 - y - z) + 1

Simplifying these equations, we get:

z = 96 - 4y - 4z + 2
y = 72 - 3y - 3z + 1

Rearranging these equations, we have:

4z + 4y = 96 - 2
3z + 4y = 73 - y

Now, we can solve these equations using any method such as substitution, elimination, or matrices to find the values of z and y. Once we have the values of z and y, we can substitute them back into the equation y = 3x + 1 to find the value of x.

Finally, combining the values of x, y, and z will give us the three-digit number.