the maximum height a typical person can jump from a crouched start is about 60cm. By how much does the gravitational potential energy increase for a 72kg person in such a jump? Where does this energy come from?

I know the formula for gravitational potential energy is U=mgh. I just don't know what to plug in =/

1. Given: m=72 kg; g (constant)=9.8 m/s^2; h= 60cm= .60m

2. Use the gravitational potential energy formula: U=mgh.
3. solve:
U=mgh
U=(72 kg)(9.8 m/s^2)(.60m)
U=423.36 kg m/s^2

72 * 9.81 * 0.60 in Joules

It comes from the kinetic energy at liftoff

prove the law of conservation of energy in the case of a sliding body?

To calculate the increase in gravitational potential energy for a 72kg person jumping from a crouched start of 60cm, we need to use the formula U = mgh, where U represents the gravitational potential energy, m is the mass, g is the acceleration due to gravity, and h is the height.

Given:
Mass (m) = 72kg
Height (h) = 60cm = 0.6m
Acceleration due to gravity (g) = 9.8 m/s^2 (approximately)

Now let's plug in these values into the formula:

U = mgh
U = (72kg) * (9.8 m/s^2) * (0.6m)
U = 423.36 Joules (approximately)

Therefore, the gravitational potential energy increases by approximately 423.36 Joules for a 72kg person in a jump from a crouched start of 60cm.

As for where this energy comes from, it is primarily derived from the conversion of chemical potential energy stored in the person's muscles. When the person crouches and then pushes off the ground to jump, their leg muscles contract and convert stored chemical energy into kinetic energy, propelling their body upward. As the person moves higher, the kinetic energy is then transformed into gravitational potential energy due to their increasing height above the ground.